Optimal. Leaf size=253 \[ -\frac{a^3}{64 d (a \sin (c+d x)+a)^4}+\frac{a^2}{96 d (a-a \sin (c+d x))^3}-\frac{a^2}{8 d (a \sin (c+d x)+a)^3}+\frac{13 a}{128 d (a-a \sin (c+d x))^2}-\frac{41 a}{64 d (a \sin (c+d x)+a)^2}+\frac{95}{128 d (a-a \sin (c+d x))}-\frac{105}{32 d (a \sin (c+d x)+a)}-\frac{\csc ^3(c+d x)}{3 a d}+\frac{\csc ^2(c+d x)}{2 a d}-\frac{5 \csc (c+d x)}{a d}-\frac{515 \log (1-\sin (c+d x))}{256 a d}-\frac{5 \log (\sin (c+d x))}{a d}+\frac{1795 \log (\sin (c+d x)+1)}{256 a d} \]
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Rubi [A] time = 0.264146, antiderivative size = 253, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.103, Rules used = {2836, 12, 88} \[ -\frac{a^3}{64 d (a \sin (c+d x)+a)^4}+\frac{a^2}{96 d (a-a \sin (c+d x))^3}-\frac{a^2}{8 d (a \sin (c+d x)+a)^3}+\frac{13 a}{128 d (a-a \sin (c+d x))^2}-\frac{41 a}{64 d (a \sin (c+d x)+a)^2}+\frac{95}{128 d (a-a \sin (c+d x))}-\frac{105}{32 d (a \sin (c+d x)+a)}-\frac{\csc ^3(c+d x)}{3 a d}+\frac{\csc ^2(c+d x)}{2 a d}-\frac{5 \csc (c+d x)}{a d}-\frac{515 \log (1-\sin (c+d x))}{256 a d}-\frac{5 \log (\sin (c+d x))}{a d}+\frac{1795 \log (\sin (c+d x)+1)}{256 a d} \]
Antiderivative was successfully verified.
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Rule 2836
Rule 12
Rule 88
Rubi steps
\begin{align*} \int \frac{\csc ^4(c+d x) \sec ^7(c+d x)}{a+a \sin (c+d x)} \, dx &=\frac{a^7 \operatorname{Subst}\left (\int \frac{a^4}{(a-x)^4 x^4 (a+x)^5} \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{a^{11} \operatorname{Subst}\left (\int \frac{1}{(a-x)^4 x^4 (a+x)^5} \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{a^{11} \operatorname{Subst}\left (\int \left (\frac{1}{32 a^9 (a-x)^4}+\frac{13}{64 a^{10} (a-x)^3}+\frac{95}{128 a^{11} (a-x)^2}+\frac{515}{256 a^{12} (a-x)}+\frac{1}{a^9 x^4}-\frac{1}{a^{10} x^3}+\frac{5}{a^{11} x^2}-\frac{5}{a^{12} x}+\frac{1}{16 a^8 (a+x)^5}+\frac{3}{8 a^9 (a+x)^4}+\frac{41}{32 a^{10} (a+x)^3}+\frac{105}{32 a^{11} (a+x)^2}+\frac{1795}{256 a^{12} (a+x)}\right ) \, dx,x,a \sin (c+d x)\right )}{d}\\ &=-\frac{5 \csc (c+d x)}{a d}+\frac{\csc ^2(c+d x)}{2 a d}-\frac{\csc ^3(c+d x)}{3 a d}-\frac{515 \log (1-\sin (c+d x))}{256 a d}-\frac{5 \log (\sin (c+d x))}{a d}+\frac{1795 \log (1+\sin (c+d x))}{256 a d}+\frac{a^2}{96 d (a-a \sin (c+d x))^3}+\frac{13 a}{128 d (a-a \sin (c+d x))^2}+\frac{95}{128 d (a-a \sin (c+d x))}-\frac{a^3}{64 d (a+a \sin (c+d x))^4}-\frac{a^2}{8 d (a+a \sin (c+d x))^3}-\frac{41 a}{64 d (a+a \sin (c+d x))^2}-\frac{105}{32 d (a+a \sin (c+d x))}\\ \end{align*}
Mathematica [A] time = 6.13887, size = 231, normalized size = 0.91 \[ \frac{a^{11} \left (\frac{95}{128 a^{11} (a-a \sin (c+d x))}-\frac{105}{32 a^{11} (a \sin (c+d x)+a)}+\frac{13}{128 a^{10} (a-a \sin (c+d x))^2}-\frac{41}{64 a^{10} (a \sin (c+d x)+a)^2}+\frac{1}{96 a^9 (a-a \sin (c+d x))^3}-\frac{1}{8 a^9 (a \sin (c+d x)+a)^3}-\frac{1}{64 a^8 (a \sin (c+d x)+a)^4}-\frac{\csc ^3(c+d x)}{3 a^{12}}+\frac{\csc ^2(c+d x)}{2 a^{12}}-\frac{5 \csc (c+d x)}{a^{12}}-\frac{515 \log (1-\sin (c+d x))}{256 a^{12}}-\frac{5 \log (\sin (c+d x))}{a^{12}}+\frac{1795 \log (\sin (c+d x)+1)}{256 a^{12}}\right )}{d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.114, size = 225, normalized size = 0.9 \begin{align*} -{\frac{1}{96\,da \left ( \sin \left ( dx+c \right ) -1 \right ) ^{3}}}+{\frac{13}{128\,da \left ( \sin \left ( dx+c \right ) -1 \right ) ^{2}}}-{\frac{95}{128\,da \left ( \sin \left ( dx+c \right ) -1 \right ) }}-{\frac{515\,\ln \left ( \sin \left ( dx+c \right ) -1 \right ) }{256\,da}}-{\frac{1}{64\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{4}}}-{\frac{1}{8\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{3}}}-{\frac{41}{64\,da \left ( 1+\sin \left ( dx+c \right ) \right ) ^{2}}}-{\frac{105}{32\,da \left ( 1+\sin \left ( dx+c \right ) \right ) }}+{\frac{1795\,\ln \left ( 1+\sin \left ( dx+c \right ) \right ) }{256\,da}}-{\frac{1}{3\,da \left ( \sin \left ( dx+c \right ) \right ) ^{3}}}+{\frac{1}{2\,da \left ( \sin \left ( dx+c \right ) \right ) ^{2}}}-5\,{\frac{1}{da\sin \left ( dx+c \right ) }}-5\,{\frac{\ln \left ( \sin \left ( dx+c \right ) \right ) }{da}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.06219, size = 306, normalized size = 1.21 \begin{align*} -\frac{\frac{2 \,{\left (3465 \, \sin \left (d x + c\right )^{9} + 2505 \, \sin \left (d x + c\right )^{8} - 10200 \, \sin \left (d x + c\right )^{7} - 6840 \, \sin \left (d x + c\right )^{6} + 10023 \, \sin \left (d x + c\right )^{5} + 5863 \, \sin \left (d x + c\right )^{4} - 3344 \, \sin \left (d x + c\right )^{3} - 1344 \, \sin \left (d x + c\right )^{2} + 64 \, \sin \left (d x + c\right ) - 128\right )}}{a \sin \left (d x + c\right )^{10} + a \sin \left (d x + c\right )^{9} - 3 \, a \sin \left (d x + c\right )^{8} - 3 \, a \sin \left (d x + c\right )^{7} + 3 \, a \sin \left (d x + c\right )^{6} + 3 \, a \sin \left (d x + c\right )^{5} - a \sin \left (d x + c\right )^{4} - a \sin \left (d x + c\right )^{3}} - \frac{5385 \, \log \left (\sin \left (d x + c\right ) + 1\right )}{a} + \frac{1545 \, \log \left (\sin \left (d x + c\right ) - 1\right )}{a} + \frac{3840 \, \log \left (\sin \left (d x + c\right )\right )}{a}}{768 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.70826, size = 979, normalized size = 3.87 \begin{align*} \frac{5010 \, \cos \left (d x + c\right )^{8} - 6360 \, \cos \left (d x + c\right )^{6} + 746 \, \cos \left (d x + c\right )^{4} + 236 \, \cos \left (d x + c\right )^{2} - 3840 \,{\left (\cos \left (d x + c\right )^{10} - 2 \, \cos \left (d x + c\right )^{8} + \cos \left (d x + c\right )^{6} -{\left (\cos \left (d x + c\right )^{8} - \cos \left (d x + c\right )^{6}\right )} \sin \left (d x + c\right )\right )} \log \left (\frac{1}{2} \, \sin \left (d x + c\right )\right ) + 5385 \,{\left (\cos \left (d x + c\right )^{10} - 2 \, \cos \left (d x + c\right )^{8} + \cos \left (d x + c\right )^{6} -{\left (\cos \left (d x + c\right )^{8} - \cos \left (d x + c\right )^{6}\right )} \sin \left (d x + c\right )\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) - 1545 \,{\left (\cos \left (d x + c\right )^{10} - 2 \, \cos \left (d x + c\right )^{8} + \cos \left (d x + c\right )^{6} -{\left (\cos \left (d x + c\right )^{8} - \cos \left (d x + c\right )^{6}\right )} \sin \left (d x + c\right )\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \,{\left (3465 \, \cos \left (d x + c\right )^{8} - 3660 \, \cos \left (d x + c\right )^{6} + 213 \, \cos \left (d x + c\right )^{4} + 38 \, \cos \left (d x + c\right )^{2} + 8\right )} \sin \left (d x + c\right ) + 112}{768 \,{\left (a d \cos \left (d x + c\right )^{10} - 2 \, a d \cos \left (d x + c\right )^{8} + a d \cos \left (d x + c\right )^{6} -{\left (a d \cos \left (d x + c\right )^{8} - a d \cos \left (d x + c\right )^{6}\right )} \sin \left (d x + c\right )\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.39332, size = 252, normalized size = 1. \begin{align*} \frac{\frac{21540 \, \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right )}{a} - \frac{6180 \, \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right )}{a} - \frac{15360 \, \log \left ({\left | \sin \left (d x + c\right ) \right |}\right )}{a} + \frac{19745 \, \sin \left (d x + c\right )^{6} - 76875 \, \sin \left (d x + c\right )^{5} + 111723 \, \sin \left (d x + c\right )^{4} - 74081 \, \sin \left (d x + c\right )^{3} + 23040 \, \sin \left (d x + c\right )^{2} - 4608 \, \sin \left (d x + c\right ) + 1024}{{\left (\sin \left (d x + c\right )^{2} - \sin \left (d x + c\right )\right )}^{3} a} - \frac{44875 \, \sin \left (d x + c\right )^{4} + 189580 \, \sin \left (d x + c\right )^{3} + 301458 \, \sin \left (d x + c\right )^{2} + 214060 \, \sin \left (d x + c\right ) + 57355}{a{\left (\sin \left (d x + c\right ) + 1\right )}^{4}}}{3072 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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